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Physics C: Mechanics Unit 2: Newton's Laws, Friction and Drag

Newton's laws connect forces to motion. This unit builds the free-body-diagram method and then applies it to friction, circular motion and velocity-dependent drag, which needs a differential equation.

Covers: Newton's three laws and free-body diagrams, Friction: static and kinetic, Inclines and connected objects, Circular motion and banked curves, Linear drag and the time constant, Quadratic drag and terminal velocity, Time-varying forces

Study guide

Newton's first law says an object keeps a constant velocity unless a net force acts, so zero net force means zero acceleration, not zero velocity. The second law, ΣF = ma, is a vector equation: write it separately for each axis. The third law says forces come in pairs that act on different objects, are equal in size, opposite in direction and the same type. The core method is the free-body diagram: isolate one object, draw every force on it (weight, normal, tension, friction, drag, applied pushes), choose axes, often along and perpendicular to the acceleration, and write ΣF = ma on each axis.

Friction opposes sliding between surfaces. Static friction takes whatever value is needed to prevent slipping, up to fₛ ≤ μₛN. Once sliding starts, kinetic friction has the fixed value fₖ = μₖN, usually smaller than the static maximum. The normal force is not always mg: on an incline it is mg cos θ, in an accelerating elevator it is m(g + a), and a rope pulling upward at an angle reduces it. For connected objects, such as blocks linked by a string, treat the whole system to find the shared acceleration, then isolate one object to find an internal force like tension or a contact force.

An object moving in a circle at speed v has centripetal acceleration v²/r toward the center. Centripetal force is not a new kind of force; it is the net inward component of real forces like tension, friction, gravity or normal force. On a flat curve friction provides it, so v_max = √(μₛgr). On a banked curve with no friction the horizontal part of the normal force provides it, giving tan θ = v²/(rg). In a vertical circle, the tension or normal force changes around the loop because gravity sometimes points toward the center and sometimes away.

Drag forces depend on velocity, so the second law becomes a differential equation. For linear drag F = −bv on a falling object, m dv/dt = mg − bv. Separating variables gives v(t) = v_t(1 − e^(−t/τ)), where the terminal speed is v_t = mg/b and the time constant is τ = m/b. After one τ the object reaches 63% of v_t, and after about 4.6τ it reaches 99%. For an object coasting horizontally, m dv/dt = −bv gives v = v₀e^(−t/τ), and it travels a finite total distance mv₀/b. Quadratic drag, F = cv², fits faster, larger objects; its terminal speed is √(mg/c).

A force that changes with time must be integrated. If F(t) is known, a(t) = F(t)/m, and the velocity change is ∫a dt. Do not plug the final force into a constant-acceleration formula. The same thinking explains why terminal speed is approached from either side: if an object moves faster than v_t, drag exceeds weight and slows it down. With drag, a thrown ball rises more quickly than it falls, because drag adds to gravity on the way up and opposes it on the way down, and it returns with a lower speed than it was launched with.

Key ideas

Formulas and rules

ΣF = ma (each axis separately)
fₛ ≤ μₛN and fₖ = μₖN
Centripetal: ΣF_in = mv²/r; flat curve v_max = √(μₛgr); ideal bank tan θ = v²/(rg)
Linear drag: v(t) = v_t(1 − e^(−t/τ)), v_t = mg/b, τ = m/b
Quadratic drag: v_t = √(mg/c)
Atwood machine: a = (m₂ − m₁)g/(m₁ + m₂)

Common mistakes

Before the test, make sure you can

Words to know

Inertia
The tendency of an object to resist changes in its velocity; measured by mass.
Net force
The vector sum of all forces acting on an object.
Free-body diagram
A sketch of one isolated object showing every external force acting on it.
Normal force
The perpendicular contact force a surface exerts on an object.
Tension
The pulling force transmitted through a string, rope or cable.
Static friction
Friction that prevents surfaces from sliding; up to μₛN.
Kinetic friction
Friction between sliding surfaces; equal to μₖN.
Apparent weight
The normal force or scale reading, which differs from mg when the object accelerates vertically.
Centripetal acceleration
Acceleration v²/r toward the center of a circular path.
Banked curve
A tilted road where the normal force helps supply the centripetal force.
Linear drag
A resistive force proportional to speed, F = −bv.
Quadratic drag
A resistive force proportional to speed squared, F = cv².
Terminal velocity
The constant speed at which drag balances the driving force.
Time constant
τ = m/b for linear drag; the time to reach 63% of terminal speed.
Conical pendulum
A mass on a string moving in a horizontal circle, with the string tracing a cone.

Sample practice questions

30 more questions like these, from level 1 to 5, are in the practice set.

Question 1 (level 1)

A hockey puck slides across frictionless ice at a constant 8 m/s. What is the net force on it?

  1. Zero
  2. Equal to its weight
  3. 8 N in the direction of motion
  4. A small force that keeps it moving
Show the answer and steps

Answer: A) Zero

  1. Newton's first law: constant velocity means zero acceleration.
  2. With a = 0, ΣF = ma = 0.
  3. No force is needed to keep an object moving; force is needed to change its velocity.
Question 2 (level 1)

Earth pulls down on a book resting on a table. According to Newton's third law, what is the reaction force to this pull?

  1. The book pushes down on the table with an equal force
  2. Friction from the table acts on the book
  3. The table pushes up on the book with an equal force
  4. The book pulls up on Earth with an equal force
Show the answer and steps

Answer: D) The book pulls up on Earth with an equal force

  1. Third-law pairs act on two different objects and are the same type of force.
  2. Earth's gravitational pull on the book pairs with the book's gravitational pull on Earth.
  3. The normal force is equal here only because the book is in equilibrium; it is not the third-law partner.
Question 3 (level 3)

Blocks of 2.0 kg and 3.0 kg sit side by side on a frictionless floor. A 20 N horizontal force pushes on the 2.0 kg block, which pushes the 3.0 kg block. What force does the 2.0 kg block exert on the 3.0 kg block?

  1. 20 N
  2. 8.0 N
  3. 12 N
  4. 4.0 N
Show the answer and steps

Answer: C) 12 N

  1. Both blocks accelerate together: a = 20/(2.0 + 3.0) = 4.0 m/s².
  2. The only horizontal force on the 3.0 kg block is the contact force.
  3. F = 3.0 × 4.0 = 12 N; 8.0 N is the net force on the 2.0 kg block.