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Linear Algebra Unit 3: Determinants
The determinant is one number that tells you whether a matrix is invertible and how it scales area or volume.
Covers: Cofactor expansion, properties, Cramer's rule, geometric meaning
Study guide
The determinant is a number attached to a square matrix. For 2×2, det[a b; c d] = ad − bc. For larger matrices, cofactor expansion goes along any row or column: multiply each entry by its cofactor (a signed smaller determinant, with signs in a checkerboard pattern) and add. Expanding along a row or column with many zeros saves work. The determinant of a triangular matrix is the product of its diagonal entries.
Row operations affect the determinant predictably: swapping two rows changes its sign, multiplying a row by k multiplies it by k, and adding a multiple of one row to another doesn't change it. So row reducing to triangular form is an efficient way to compute determinants.
Key properties: det(AB) = det A·det B, det(Aᵀ) = det A, det(A⁻¹) = 1/det A, and det(cA) = cⁿ det A for an n×n matrix. A is invertible exactly when det A ≠ 0; a zero determinant means the matrix is singular.
Cramer's rule solves Ax = b when det A ≠ 0: xᵢ = det Aᵢ/det A, where Aᵢ is A with column i replaced by b. It's elegant for small systems but slow for large ones.
Geometrically, |det A| is the factor by which the transformation x ↦ Ax scales area (2D) or volume (3D), and a negative determinant means orientation is reversed.
The inverse can be written with cofactors as A⁻¹ = (1/det A)·Cᵀ, where C is the matrix of cofactors. Note the transpose: entry (i, j) of A⁻¹ is the cofactor C_ji divided by det A. A permutation matrix has determinant +1 or −1, depending on whether an even or odd number of row swaps reorders it to I. Because det A is the product of the eigenvalues, structured matrices are often easiest that way. For example, the n×n all-ones matrix J has eigenvalues n, 0, …, 0, so J − I has eigenvalues n − 1, −1, …, −1.
For a tridiagonal matrix, expanding along the first row and then expanding the leftover minor gives a recurrence of the form Dₙ = a·Dₙ₋₁ − bc·Dₙ₋₂. Compute D₁ and D₂ directly, then iterate.
Key ideas
- det A ≠ 0 ⇔ A is invertible.
- Cofactor expansion works along any row or column. Pick one with many zeros.
- Row swaps flip the sign; scaling a row scales the determinant; adding a multiple of a row changes nothing.
- Triangular matrices: determinant is the product of the diagonal.
- |det A| is the factor by which A scales areas or volumes.
Formulas and rules
Common mistakes
- Writing det(A + B) = det A + det B.
- Forgetting det(cA) uses cⁿ, not c.
Words to know
- Singular matrix
- det A = 0; not invertible.
- det of a triangular matrix
- The product of the diagonal entries.
- Effect of swapping two rows on det
- It changes sign.
- det(AB)
- det A · det B
- Determinant of a scalar multiple
- det(cA) = cⁿ·det A for an n×n matrix.
- Geometric meaning of |det A|
- How much A scales area (2D) or volume (3D).
- Determinant (2×2)
- ad − bc
- Cofactor expansion
- Multiply entries of a row or column by their signed cofactors and add.
- Cofactor
- (−1)ⁱ⁺ʲ times the determinant left after deleting row i and column j.
- Row scaling and det
- Multiplying a row by k multiplies the determinant by k.
- Row replacement and det
- Adding a multiple of one row to another leaves det unchanged.
- det(Aᵀ)
- det A
- Cramer's rule
- xᵢ = det Aᵢ / det A
Sample practice questions
29 more questions like these, from level 1 to 5, are in the practice set.
det [4 1; 2 3]
- 10
- 14
- −10
- 12
Show the answer and steps
Answer: A) 10
- det [a b; c d] = ad − bc.
- 4·3 − 1·2 = 10.
Determinant of a triangular matrix with diagonal 2, 3, 4.
- 0
- 9
- 20
- 24
Show the answer and steps
Answer: D) 24
- Triangular matrix: determinant = product of the diagonal.
- 2 × 3 × 4 = 24.
A is 3 × 3 with det A = 5. Find det(2A).
- 10
- 40
- 25
- 30
Show the answer and steps
Answer: B) 40
- det(kA) = kⁿ det A for n × n.
- 2³ × 5 = 40.