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Introductory Statistics Unit 8: Inference for means

When the data are measurements, you estimate or test a population mean with t-procedures, because the population SD is usually unknown.

Covers: t-procedures for one mean, two independent means, matched pairs

Study guide

Inference for means uses the t-distribution because the population standard deviation σ is almost never known and is estimated by the sample standard deviation s. The t-distributions are bell-shaped like the normal but have heavier tails, and they depend on degrees of freedom: for one sample, df = n − 1. As df increases, t approaches the standard normal.

A one-sample t interval is x̄ ± t*·s/√n, and a one-sample t test uses t = (x̄ − μ₀)/(s/√n). Conditions: random sample, the 10% condition, and Normal/large sample: the population is normal, or n ≥ 30, or for small samples a graph of the data shows no strong skew or outliers.

Two independent samples compare two population means with (x̄₁ − x̄₂) ± t*·√(s₁²/n₁ + s₂²/n₂), and the test statistic t = (x̄₁ − x̄₂)/√(s₁²/n₁ + s₂²/n₂). Use technology for the degrees of freedom, or the smaller of n₁ − 1 and n₂ − 1 as a conservative choice. Check conditions for each group.

Matched pairs data come from the same individuals measured twice (before and after) or from paired subjects. Don't use two-sample methods: compute the difference for each pair and run a one-sample t procedure on the differences, with μ_d as the parameter.

Interpret intervals and tests in context, with units, and connect them: a 95% interval that excludes μ₀ corresponds to rejecting H₀ at α = 0.05 in a two-sided test.

Statistical significance doesn't guarantee practical importance, because very large samples can make tiny differences significant. An effect size such as Cohen's d = (x̄₁ − x̄₂)/s_pooled measures a difference in standard-deviation units: about 0.2 is small, 0.5 medium and 0.8 large. Define the parameter in words with context, for example "μ = the true mean commute time, in minutes, for all students at the school."

A one-sided test uses the area in the tail that points in the direction of Hₐ. A two-sided test doubles the area of one tail. Greater variability (a larger s) widens confidence intervals, shrinks test statistics, and lowers both power and effect size.

Key ideas

Formulas and rules

CI: x̄ ± t*·s/√n, df = n − 1
Test: t = (x̄ − μ₀) / (s/√n)
Two-sample: t = (x̄₁ − x̄₂) / √(s₁²/n₁ + s₂²/n₂)

Common mistakes

Words to know

One-sample t interval
x̄ ± t*·s/√n with df = n − 1
One-sample t test statistic
t = (x̄ − μ₀) / (s/√n)
t-distribution
Used for means when σ is unknown and estimated by s.
Matched pairs
Analyze the differences with a one-sample t procedure.
Normal/large sample condition for t
Population is normal, or n ≥ 30, or a small sample shows no strong skew or outliers.
Degrees of freedom (t)
As df increases, t approaches the standard normal.
Two-sample t statistic
t = (x̄₁ − x̄₂) / √(s₁²/n₁ + s₂²/n₂)
Standard error of the mean
s/√n
t* critical value
From the t-distribution with n − 1 df for the chosen confidence level.
Two-sample t interval
(x̄₁ − x̄₂) ± t*·√(s₁²/n₁ + s₂²/n₂)
Matched pairs parameter (μ_d)
The mean of the differences.
Robust procedure
Still accurate when conditions are mildly violated; t procedures are robust for large n.

Sample practice questions

21 more questions like these, from level 1 to 5, are in the practice set.

Question 1 (level 1)

x̄ = 20, s = 4, n = 16. Standard error?

  1. 4
  2. 1
  3. 5
  4. 0.25
Show the answer and steps

Answer: B) 1

  1. SE = s/√n.
  2. 4/√16 = 1.
Question 2 (level 1)

A one-sample t procedure uses n = 36. Degrees of freedom?

  1. 6
  2. 35
  3. 36
  4. 34
Show the answer and steps

Answer: B) 35

  1. df = n − 1.
  2. 36 − 1 = 35.
Question 3 (level 3)

Test H₀: μ = 18 with that sample. t = ?

  1. 2
  2. 0.5
  3. 18
  4. 8
Show the answer and steps

Answer: A) 2

  1. t = (x̄ − μ₀)/SE.
  2. (20 − 18)/1 = 2.