Home / Courses / College Algebra / Unit 8
College Algebra Unit 8: Polynomial & rational functions
Polynomial and rational functions are the workhorses of algebra. Their zeros, end behavior and asymptotes tell you what the graph looks like.
Covers: End behavior, zeros & multiplicity, division, asymptotes
Study guide
Polynomial functions have end behavior set by the leading term. Even degree: both ends point the same way, up if the leading coefficient is positive and down if negative. Odd degree: the ends point opposite ways. A degree-n polynomial has at most n real zeros and at most n − 1 turning points.
Zeros come from factors. A factor (x − c)ᵏ gives a zero at c with multiplicity k: odd multiplicity crosses the x-axis and even multiplicity touches and turns. Use long division or synthetic division to divide polynomials. The Remainder Theorem says dividing f(x) by (x − c) leaves remainder f(c), and the Factor Theorem says f(c) = 0 exactly when (x − c) is a factor. The Rational Zero Theorem lists possible rational zeros as ±(factors of the constant)/(factors of the leading coefficient); test them, and divide out each zero you find.
Rational functions are ratios of polynomials. After factoring and canceling, a canceled factor leaves a hole, and a remaining denominator factor gives a vertical asymptote. Horizontal asymptotes compare degrees: a bottom degree bigger gives y = 0, equal degrees give y = ratio of leading coefficients, and a top degree bigger by one gives a slant asymptote found by division. Graphs can cross horizontal asymptotes but never vertical ones.
A polynomial of degree n has exactly n complex zeros, counting multiplicity. If its coefficients are real, nonreal zeros come in conjugate pairs: if 2 + i is a zero, so is 2 − i. If a polynomial's values at x = a and x = b have opposite signs, it has a real zero between a and b. Checking consecutive integers this way locates zeros.
To write a polynomial with given zeros r₁, r₂, …, use f(x) = a(x − r₁)(x − r₂)···, then find a from one more known point on the graph.
Key ideas
- End behavior of a polynomial depends on the leading term's degree and sign.
- A zero with odd multiplicity crosses the x-axis; even multiplicity touches and turns.
- Use long or synthetic division to divide polynomials; the Remainder Theorem says f(c) is the remainder when dividing by (x − c).
- Rational Zero Theorem: possible rational zeros are ±(factors of constant)/(factors of leading coefficient).
- Rational functions have vertical asymptotes where the reduced denominator is zero and holes where a factor cancels.
Formulas and rules
Common mistakes
- Calling a canceled factor a vertical asymptote. It's a hole.
- Assuming a graph can never cross a horizontal asymptote (it can, in the middle).
Words to know
- End behavior
- Set by the leading term: −2x⁵ rises left, falls right.
- Even multiplicity zero
- The graph touches the x-axis and turns around.
- Remainder Theorem
- Dividing f(x) by (x − c) leaves remainder f(c).
- Vertical asymptote vs hole
- Asymptote: denominator zero after reducing. Hole: a factor that cancels.
- Horizontal asymptote when the bottom has higher degree
- y = 0
- Factor Theorem
- f(c) = 0 exactly when (x − c) is a factor.
- Turning points
- A degree-n polynomial has at most n − 1.
- Synthetic division
- Shortcut for dividing by (x − c).
- Rational Zero Theorem
- Possible rational zeros: ±(factors of constant)/(factors of leading coefficient).
- Hole
- A canceled factor leaves a single missing point.
- Slant asymptote
- When the top's degree is one more than the bottom's; found by division.
- Crossing a horizontal asymptote
- Possible; graphs never cross vertical asymptotes.
Sample practice questions
27 more questions like these, from level 1 to 5, are in the practice set.
Zeros of f(x) = (x − 1)(x + 4).
- 1 and −4
- 1 and 4
- −1 and 4
- 0 and −4
Show the answer and steps
Answer: A) 1 and −4
- Set each factor to zero.
- x − 1 = 0 → x = 1; x + 4 = 0 → x = −4.
Find the vertical asymptotes of 1/(x² + 7x + 10).
- x = −5 and x = −2
- y = −5 and y = −2
- x = 5 and x = 2
- x = 10
Show the answer and steps
Answer: A) x = −5 and x = −2
- Factor the bottom: (x + 5)(x + 2).
- It's zero at x = −5 and x = −2, and nothing cancels.
Vertical asymptote(s) of (x − 2)/((x − 2)(x + 5)).
- None
- x = 2 only
- x = −5 only
- x = 2 and x = −5
Show the answer and steps
Answer: C) x = −5 only
- Factor and cancel x − 2 (that's a hole at x = 2).
- What's left is 1/(x + 5).
- The only vertical asymptote is x = −5.