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Calculus III (Multivariable) Unit 7: Vector calculus
Vector fields assign a vector to every point. Line integrals add up a field along a curve, which in physics is work.
Covers: Vector fields, line integrals, conservative fields, Green's theorem
Study guide
A vector field F assigns a vector to every point, like wind velocity or a force. In 2D, F = ⟨P, Q⟩; in 3D, F = ⟨P, Q, R⟩. Gradient fields F = ∇f come from a scalar potential function f.
A line integral adds a quantity along a curve C. For a scalar function, ∫_C f ds uses arc length, ds = |r′(t)| dt. For a vector field, ∫_C F·dr = ∫ F(r(t))·r′(t) dt measures work done by a force along a path, or flow along a curve. Parametrize the curve, substitute, and integrate in t. Reversing the direction of C changes the sign.
A conservative field is a gradient field. Its line integrals are path-independent and given by the Fundamental Theorem for line integrals: ∫_C ∇f·dr = f(end) − f(start). Around any closed loop the integral is 0. In 2D, on a simply connected region, F = ⟨P, Q⟩ is conservative when ∂P/∂y = ∂Q/∂x. To find the potential, integrate P with respect to x, then match ∂f/∂y with Q to fix the remaining function of y.
Green's theorem converts a line integral around a closed curve into a double integral over the region inside: ∮_C P dx + Q dy = ∬_D (∂Q/∂x − ∂P/∂y) dA, with C oriented counterclockwise. It can also compute areas, for example using ½∮ x dy − y dx.
The outward flux of F = ⟨P, Q⟩ across a closed curve C is ∮_C F·n ds = ∮_C P dy − Q dx = ∬_D (∂P/∂x + ∂Q/∂y) dA, with C traversed counterclockwise. This is the 2D divergence theorem. For a curve traversed counterclockwise, the outward normal times ds is ⟨dy, −dx⟩. Along any segment where F is parallel to the curve, the flux is 0.
In 3D, F = ⟨P, Q, R⟩ is conservative on a simply connected region when curl F = 0, which means R_y = Q_z, P_z = R_x and Q_x = P_y. A positive net outward flux means more of the field leaves the region than enters it (a net source). A positive circulation means a net counterclockwise flow around the curve.
Key ideas
- Line integral of a scalar function: ∫_C f ds.
- Work: ∫_C F·dr.
- A conservative field is a gradient F = ∇f; its line integrals depend only on the endpoints.
- Test in 2D: F = ⟨P, Q⟩ is conservative on a simply connected region if ∂P/∂y = ∂Q/∂x.
- Green's theorem turns a line integral around a closed curve into a double integral over its interior.
Formulas and rules
Common mistakes
- Using Green's theorem on a curve that isn't closed.
- Going clockwise when Green's theorem assumes counterclockwise.
Words to know
- Work done by F along C
- ∫_C F·dr
- Conservative vector field
- The gradient of a potential function f; path-independent.
- 2D test for conservative F = ⟨P, Q⟩
- ∂P/∂y = ∂Q/∂x (on a simply connected region).
- Green's theorem
- ∮_C P dx + Q dy = ∬_D (Q_x − P_y) dA
- ∮ of a conservative field around a closed loop
- 0
- Fundamental theorem for line integrals
- ∫_C ∇f·dr = f(end) − f(start)
- Vector field
- A vector assigned to every point, like F = ⟨P, Q⟩.
- Gradient field
- F = ∇f for a potential function f.
- Line integral of a scalar function
- ∫_C f ds, with ds = |r′(t)| dt.
- Line integral of a vector field
- ∫_C F·dr = ∫ F(r(t))·r′(t) dt: work or circulation.
- Path independence
- A conservative field's line integral depends only on the endpoints.
- Potential function
- f with ∇f = F.
- Area by Green's theorem
- ½∮ x dy − y dx
Sample practice questions
17 more questions like these, from level 1 to 5, are in the practice set.
F = ⟨2x, 2y⟩ is the gradient of…
- 4xy
- x² + y²
- 2x + 2y
- x²y²
Show the answer and steps
Answer: B) x² + y²
- Find f with f_x = 2x and f_y = 2y.
- f = x² + y².
Is F = ⟨y, x⟩ conservative?
- Yes, F = ∇(xy)
- Only for x > 0
- Can't tell
- No
Show the answer and steps
Answer: A) Yes, F = ∇(xy)
- Test: ∂P/∂y = ∂(y)/∂y = 1 and ∂Q/∂x = ∂(x)/∂x = 1.
- Equal, so conservative; f = xy works.
f = x²y. Find ∫_C ∇f · dr from (0, 0) to (2, 3).
- 12
- 0
- 18
- 6
Show the answer and steps
Answer: A) 12
- ∫ ∇f · dr = f(end) − f(start).
- f(2, 3) = 4·3 = 12, f(0, 0) = 0.
- 12.