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Calculus III (Multivariable) Unit 3: Functions of several variables

Functions of several variables have a partial derivative for each input. Each one measures change in a single direction while the others are held fixed.

Covers: Limits & continuity, partial derivatives, tangent planes, chain rule

Study guide

Functions of several variables, like z = f(x, y), take multiple inputs. Their graphs are surfaces, and their level curves f(x, y) = k form contour maps. The domain is a region of the plane.

Limits in two variables must give the same value along every path to the point. To show a limit doesn't exist, find two paths (such as along the x-axis and along y = x) that give different values. A function is continuous where its limit equals its value; polynomials and most familiar combinations are continuous on their domains.

Partial derivatives measure the rate of change in one variable while holding the others constant. To find ∂f/∂x, treat y as a constant and differentiate with respect to x. Second partials include f_xx, f_yy and mixed partials f_xy and f_yx, which are equal when they're continuous (Clairaut's theorem).

The tangent plane to z = f(x, y) at (x₀, y₀) is z − z₀ = f_x(x₀, y₀)(x − x₀) + f_y(x₀, y₀)(y − y₀). It gives the linear approximation of f near that point, and the total differential dz = f_x dx + f_y dy estimates small changes.

The multivariable chain rule follows every path from the output to the variable: if z = f(x, y) with x and y depending on t, then dz/dt = f_x·dx/dt + f_y·dy/dt. Implicit differentiation follows: dy/dx = −F_x/F_y for F(x, y) = 0.

When several equations tie variables together, take the differential of each one (for example d(x²y) = 2xy dx + x² dy), substitute the point, and solve the resulting linear equations for the ratio you need, such as dy/dx or ∂z/∂x. If z = f(x, y) with x = x(s, t) and y = y(s, t), then ∂z/∂s = f_x·∂x/∂s + f_y·∂y/∂s, and similarly for ∂z/∂t. A tree diagram from z down to s and t shows every term.

If F(x, y, z) = 0 defines z implicitly, then ∂z/∂x = −F_x/F_z and ∂z/∂y = −F_y/F_z. In a linear approximation Δf ≈ f_x Δx + f_y Δy, the input whose partial derivative times its possible change is largest in size has the biggest effect on f.

Key ideas

Formulas and rules

Tangent plane: z − z₀ = f_x(x₀, y₀)(x − x₀) + f_y(x₀, y₀)(y − y₀)
Chain rule: dz/dt = f_x·dx/dt + f_y·dy/dt
f_xy = f_yx (Clairaut)

Common mistakes

Words to know

Partial derivative ∂f/∂x
Differentiate in x, treating other variables as constants.
Clairaut's theorem
Continuous mixed partials are equal: f_xy = f_yx.
Tangent plane to z = f(x, y) at (x₀, y₀)
z − z₀ = f_x(x − x₀) + f_y(y − y₀)
Chain rule for z = f(x(t), y(t))
dz/dt = f_x·x′(t) + f_y·y′(t)
Two-path test
Different limits along two paths → the limit doesn't exist.
Function of two variables
z = f(x, y), graphed as a surface.
Level curve
The curve f(x, y) = k; together they form a contour map.
Limit in two variables
Must give the same value along every path.
Mixed partial derivatives
f_xy and f_yx.
Linear approximation (2 variables)
f(x, y) ≈ f(a, b) + f_x(x − a) + f_y(y − b)
Total differential
dz = f_x dx + f_y dy
Implicit differentiation (multivariable)
dy/dx = −F_x/F_y for F(x, y) = 0.

Sample practice questions

29 more questions like these, from level 1 to 5, are in the practice set.

Question 1 (level 1)

f = x²y + 3y. Find f_x.

  1. x² + 3
  2. 2xy
  3. 2x
  4. 2xy + 3
Show the answer and steps

Answer: B) 2xy

  1. Treat y as a constant.
  2. ∂/∂x (x²y + 3y) = 2xy.
Question 2 (level 2)

Same f. Find f_y.

  1. 3
  2. 2xy
  3. x² + 3
  4. x²
Show the answer and steps

Answer: C) x² + 3

  1. Treat x as a constant.
  2. ∂/∂y (x²y + 3y) = x² + 3.
Question 3 (level 3)

f = x²y³. Find f_xy.

  1. 6x²y
  2. 6xy²
  3. 2xy³
  4. 3x²y²
Show the answer and steps

Answer: B) 6xy²

  1. f_x = 2xy³.
  2. f_xy = ∂/∂y (2xy³) = 6xy².