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Calculus I (Differential & intro Integral) Unit 2: Definition of the derivative
The derivative measures the instantaneous rate of change of a function, which is also the slope of its tangent line. It's defined as a limit of average rates of change.
Covers: Difference quotient, derivative as rate/slope, differentiability vs continuity, power/sum/product/quotient rules
Study guide
The derivative measures instantaneous rate of change. Start with the difference quotient [f(x + h) − f(x)]/h, which is the slope of a secant line, the average rate of change over a small interval. Taking the limit as h → 0 gives the derivative: f′(x) = lim h→0 [f(x + h) − f(x)]/h. Geometrically, f′(a) is the slope of the tangent line at x = a; in context it's a rate with units of output per input.
A function is differentiable at a point if this limit exists. Differentiability implies continuity, but not the other way: a continuous function can fail to be differentiable at a corner (like |x| at 0), a cusp, or a vertical tangent. Any discontinuity also prevents differentiability.
Rules make derivatives fast. The power rule gives d/dx xⁿ = nxⁿ⁻¹. The constant multiple and sum rules let you differentiate term by term. The product rule is (fg)′ = f′g + fg′, and the quotient rule is (f/g)′ = (f′g − fg′)/g². Memorize the basic derivatives: d/dx sin x = cos x, d/dx cos x = −sin x, d/dx eˣ = eˣ, and d/dx ln x = 1/x.
Use the derivative to write tangent lines with point-slope form: y − f(a) = f′(a)(x − a).
An equivalent definition is f′(a) = lim x→a [f(x) − f(a)]/(x − a). If you recognize a limit in either form as a derivative, you can evaluate it immediately: lim x→3 (ln x − ln 3)/(x − 3) is the derivative of ln x at 3, which is 1/3. When f is known only from a table, estimate f′(a) with the average rate of change over the smallest table interval that contains a, [f(b) − f(c)]/(b − c), and give units of output per unit of input.
Two curves have parallel tangent lines at x = c exactly when f′(c) = g′(c), and a graph has a horizontal tangent where f′(c) = 0. To find such points, set up the equation in the derivatives and solve it.
Key ideas
- Limit definition: f′(x) = lim h→0 [f(x + h) − f(x)] / h.
- Average rate of change over [a, b] is the secant slope; the derivative is what that slope approaches as the interval shrinks.
- Differentiable implies continuous, but not the other way around. Corners, cusps, vertical tangents and discontinuities all break differentiability.
- Power, constant-multiple and sum rules handle polynomials. Product and quotient rules handle combinations.
Formulas and rules
Common mistakes
- Using (fg)′ = f′g′. The product rule has two terms.
- Mixing up the order in the quotient rule numerator (it's low·d-high minus high·d-low).
Words to know
- Limit definition of the derivative
- f′(x) = lim h→0 [f(x + h) − f(x)] / h
- Power rule
- d/dx xⁿ = n·xⁿ⁻¹
- Product rule
- (fg)′ = f′g + fg′
- Quotient rule
- (f/g)′ = (f′g − fg′) / g²
- d/dx cos x
- −sin x
- d/dx ln x
- 1/x (for x > 0)
- Differentiability vs. continuity
- Differentiable implies continuous, but not the reverse (|x| at 0).
- Where differentiability fails
- Corners, cusps, vertical tangents and discontinuities.
- Derivative
- f′(x): the instantaneous rate of change and the slope of the tangent line.
- Difference quotient
- [f(x + h) − f(x)]/h: an average rate of change.
- Tangent line equation
- y − f(a) = f′(a)(x − a)
- Constant multiple rule
- (cf)′ = c·f′
- Sum rule (derivatives)
- (f + g)′ = f′ + g′
- d/dx sin x
- cos x
- d/dx eˣ
- eˣ
Sample practice questions
37 more questions like these, from level 1 to 5, are in the practice set.
d/dx x⁵
- 5x⁴
- 4x⁵
- x⁴
- 5x⁵
Show the answer and steps
Answer: A) 5x⁴
- Power rule: d/dx xⁿ = n·xⁿ⁻¹.
- d/dx x⁵ = 5x⁴.
Find d/dx (x⁵).
- x⁴
- 5x⁴
- 5x⁵
- 4x⁴
Show the answer and steps
Answer: B) 5x⁴
- Power rule: d/dx (axⁿ) = a·n·xⁿ⁻¹.
- 1·5·x⁴ = 5x⁴.
d/dx (x² sin x)
- 2x sin x + x² cos x
- 2x sin x − x² cos x
- x² cos x
- 2x cos x
Show the answer and steps
Answer: A) 2x sin x + x² cos x
- Product rule: (fg)′ = f′g + fg′ with f = x², g = sin x.
- f′ = 2x, g′ = cos x.
- 2x sin x + x² cos x.